7x^2+3x=180

Solution for 7x^2+3x=180 equation:

7x^2+3x=180

We move all terms to the left:

7x^2+3x-(180)=0

a = 7; b = 3; c = -180;
Δ = b2-4ac
Δ = 32-4·7·(-180)
Δ = 5049
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5049}=\sqrt{9*561}=\sqrt{9}*\sqrt{561}=3\sqrt{561}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3\sqrt{561}}{2*7}=\frac{-3-3\sqrt{561}}{14}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3\sqrt{561}}{2*7}=\frac{-3+3\sqrt{561}}{14}
$